Solution 18.8d

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  • (cur) (last) 18:52, 8 October 2010 Ian (Talk | contribs) (208 bytes) (New page: <math>\mathbf{a}=\frac{d\mathbf{v}}{dt}=-\frac{1}{5}\mathbf{i}\ \text{m}{{\text{s}}^{-2}}</math> This is a constant vector pointing in the opposite direction to <math>\mathbf{i}</math>, ...)
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