Solution 18.7b

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  • (cur) (last) 18:23, 8 October 2010 Ian (Talk | contribs) (283 bytes) (New page: <math>\begin{align} & \mathbf{v}=\frac{d\mathbf{r}}{dt}=40\mathbf{i}+(6t+20)\mathbf{j} \\ & \mathbf{v}(10)=40\mathbf{i}+(6\times 10+20)\mathbf{j}=40\mathbf{i}+80\mathbf{j} \\ & v(10)=\sq...)
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