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• (cur) (last) 12:09, 4 October 2010 Ian (Talk | contribs) (219 bytes) (New page: Gain in kinetic energy = Loss in potential energy. <math>\begin{align} & 40\times 9 \textrm{.}8\times 12=\frac{1}{2}\times 40\times {{v}^{2}} \\ & v=15 \textrm{.}3\text{ m}{{\text{s}}^{\...)

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