Solution 16.3

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  • (cur) (last) 16:21, 23 September 2010 Ian (Talk | contribs) (358 bytes) (New page: Using <math>{{m}_{A}}{{v}_{A}}+{{m}_{B}}{{v}_{B}}={{m}_{A}}{{u}_{A}}+{{m}_{B}}{{u}_{B}}</math> <math>\begin{align} & 3\times 4+5\times (-2)=3\times 0+5v \\ & 12-10=5v \\ & v=\frac{2}{5...)
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