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for Solution 16.10b

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From part a)

<math>(5m+2\lambda m-3m-3\lambda m)\mathbf{i}+(mV-\lambda mV+2m+2\lambda m)\mathbf{j}=0\mathbf{i}+0\mathbf{j}</math>

Consider the 
<math>\mathbf{j}</math>
component. That is the <math>\mathbf{j}</math> component on the left hand side must be the same as the <math>\mathbf{j}</math> component on the right hand side, that is zero.

<math>\begin{align}
& mV-\lambda mV+2m+2\lambda m=0 \\ 
& V-2V+2+4=0 \\ 
& -V+6=0 \\ 
& V=6 \\ 
\end{align}</math>

Note that <math>V</math> is a dimensionless number.

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