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  1. 2. Exercises (3,472 bytes)
    5: {{Selected tab|[[2. Exercises|Exercises]]}}
    62: ===Exercise 2.6===
    66: ...#NAVCONTENT:Answer|Answer 2.6|Solution|Solution 2.6}}
    71: ...h>\text{1}\textrm{.}\text{73}\times \text{1}{{0}^{6}}</math> m. Determine the acceleration due to gra...
    100: The mass of Mars is <math>\text{6}\textrm{.}\text{42}\times \text{1}{{0}^{23}}</mat...
  2. 3. Exercises (5,734 bytes)
    5: {{Selected tab|[[3. Exercises|Exercises]]}}
    61: ===Exercise 3.6===
    72: ...nswer 3.6a|Answer b|Answer 3.6b|Answer c|Answer 3.6c}}
    100: ...tude of the friction force on the box if <math>P=760\text{ N}</math>.
    167: ... of friction between the tank and the ground is 0.6. The rope exerts a horizontal force of magnitude ...
  3. 4. Exercises (4,452 bytes)
    5: {{Selected tab|[[4. Exercises|Exercises]]}}
    42: 6 <math>\mathbf{i}</math><math>+</math>8
    90: ===Exercise 4.6===
    95: [[Image:E4.6.GIF]]
    103: ...6a|Solution b|Solution 4.6b|Solution c|Solution 4.6c}}
  4. 5. Exercises (4,879 bytes)
    5: {{Selected tab|[[5. Exercises|Exercises]]}}
    101: ===Exercise 5.6===
    113: ...r 5.6b|Answer c|Answer 5.6c|Solution c|Solution 5.6c}}
  5. 6. Exercises (5,072 bytes)
    4: {{Not selected tab|[[6. Kinematics in one dimension|Theory]]}}
    5: {{Selected tab|[[6. Exercises|Exercises]]}}
    6: {{Not selected tab|[[6. Video|Video]]}}
    10: ===Exercise 6.1===
    15: [[Image:E6.1.GIF]]
  6. 7. Exercises (3,029 bytes)
    5: {{Selected tab|[[7. Exercises|Exercises]]}}
    15: <math>\mathbf{r}=6t\mathbf{i}+\left( 15t-4\textrm{.}9{{t}^{2}} \righ...
    62: <math>\mathbf{r}=(2t-16)\mathbf{i}+(4t-12)\mathbf{j}</math>
  7. 8. Exercises (8,050 bytes)
    5: {{Selected tab|[[8. Exercises|Exercises]]}}
    51: ...> and is at the point with position vector (<math>6\mathbf{i}+2\mathbf{j}</math>) m.
    57: ... of the particle (<math>4\textrm{.}8\mathbf{i}– 6\textrm{.}8\mathbf{j}</math>) <math>\text{m}{{\te...
    77: ===Exercise 8.6===
    81: ...h> until after 10 seconds its velocity is (<math>6\mathbf{i}-8\mathbf{j}</math>) <math>\text{m}{{\...
  8. 9. Exercises (2,456 bytes)
    5: {{Selected tab|[[9. Exercises|Exercises]]}}
    47: A skier of mass 60 kg is travelling at a constant speed down a slop...
    52: ===Exercise 9.6===
    55: A car of mass 1600 kg is towed up a hill of inclined at 5<math>{}^...
    57: [[Image:E9.6.GIF]]
  9. 10. Exercises (2,954 bytes)
    5: {{Selected tab|[[10. Exercises|Exercises]]}}
    44: A particle of mass 6 kg starts from rest and accelerates uniformly. Th...
    56: ===Exercise 10.6===
    61: ...AVCONTENT:Answer|Answer 10.6|Solution|Solution 10.6}}
  10. 11. Exercises (1,991 bytes)
    5: {{Selected tab|[[11. Exercises|Exercises]]}}
  11. 13. Exercises (1,182 bytes)
    5: {{Selected tab|[[13. Exercises|Exercises]]}}
    32: ...ver. The angle between the lever and the force is 60<math>{}^\circ </math>. Find the moment of this f...
  12. 14. Exercises (3,793 bytes)
    5: {{Selected tab|[[14. Exercises|Exercises]]}}
    31: ...he plank which is on the ground. A person of mass 60 kg walks on the part of plank that is over the w...
    43: A uniform beam has mass 20 kg and length 6 m. It rests on two supports that are 1.5 m from e...
    53: A uniform rod of mass 18 kg and length 6m rests on two supports.
    74: A metal beam, of mass 6 kg and length 2m, rests in a horizontal position ...
  13. 15. Exercises (5,088 bytes)
    5: {{Selected tab|[[15. Exercises|Exercises]]}}
    18: c) a car, of mass 1200 kg, travelling at 36 kmph.
    73: ===Exercise 15.6===
    83: ...|Solution a|Solution 15.6a|Solution b|Solution 15.6b}}
    90: ...itting the wall, the particle moves at a speed of 6 <math>\text{m}{{\text{s}}^{-1}}</math> at right a...
  14. 16. Exercises (5,467 bytes)
    4: {{Not selected tab|[[16. Conservation of momentum|Theory]]}}
    5: {{Selected tab|[[16. Exercises|Exercises]]}}
    12: ===Exercise 16.1===
    18: ...#NAVCONTENT:Answer|Answer 16.1|Solution|Solution 16.1}}
    22: ===Exercise 16.2===
  15. 17. Exercises (4,927 bytes)
    5: {{Selected tab|[[17. Exercises|Exercises]]}}
    73: ===Exercise 17.6===
    78: [[Image:E17.6.GIF]]
    88: ...|Solution b|Solution 17.6b|Solution c|Solution 17.6c}}
  16. 18. Exercises (6,749 bytes)
    5: {{Selected tab|[[18. Exercises|Exercises]]}}
    19: <math>s=\frac{{{t}^{3}}}{3}-\frac{{{t}^{4}}}{60}</math>
    43: <math>s=5{{t}^{2}}-6t</math>.
    128: ===Exercise 18.6===
    151: ...|Solution b|Solution 18.6b|Solution c|Solution 18.6c}}
  17. 19. Exercises (6,277 bytes)
    5: {{Selected tab|[[19. Exercises|Exercises]]}}
    116: ===Exercise 19.6===
    129: ...|Solution a|Solution 19.6a|Solution b|Solution 19.6b}}
    141: <math>\mathbf{F}=12t\mathbf{i}+(6-5t)\mathbf{j}</math>
  18. 20. Exercises (2,958 bytes)
    5: {{Selected tab|[[20. Exercises|Exercises]]}}
    31: ...takes a bend, of radius 50 m, on a level road, at 60 km/h, without sliding. Find the frictional force...
    40: ... friction between the coin and the turntable is 0.6.
    66: ===Exercise 20.6===
    76: ...|Solution a|Solution 20.6a|Solution b|Solution 20.6b}}

Page text matches

  1. 2. Introduction to force and gravity (4,624 bytes)
    5: {{Not selected tab|[[2. Exercises|Exercises]]}}
    38: <math>G=6\textrm{.}67\times 10^{-11}\text{ kg}^{\text{-1}}\text{m}^{\t...
    67: ...text{6}\textrm{.}\text{37}\times \text{1}0^{\text{6}}\text{ }</math>
    104: & =215600\text{ N}
    113: <math>{{R}_{1}}+{{R}_{2}}+{{R}_{3}}+{{R}_{4}}=215600\ \text{N}</math>
  2. 3. Other types of force (5,193 bytes)
    6: {{Not selected tab|[[3. Exercises|Exercises]]}}
    127: <math>{{T}_{2}}=117\textrm{.}6\text{ N}</math>
    137: <math>R=196</math> N
    150: & F=117\textrm{.}6-78\textrm{.}4 \\
    160: & 39\textrm{.}2\le \mu \times 196 \\
  3. 4. Forces and vectors (4,578 bytes)
    5: {{Not selected tab|[[4. Exercises|Exercises]]}}
    134: ...>\theta ={{\tan }^{-1}}\left( \frac{8}{4} \right)=63\textrm{.}4{}^\circ </math>
    164: ...}^\circ +15\sin 30{}^\circ \right)\mathbf{j}=-23.627\mathbf{i}-3.730\mathbf{j} \text{ N}
    169: <math>\sqrt{{{23\textrm{.}627}^{2}}+{{3\textrm{.}730}^{2}}}=23\textrm{.}9\tex...
    174: & \tan \theta =\frac{3\textrm{.}730}{23\textrm{.}627} \\
  4. 2. Exercises (3,472 bytes)
    5: {{Selected tab|[[2. Exercises|Exercises]]}}
    62: ===Exercise 2.6===
    66: ...#NAVCONTENT:Answer|Answer 2.6|Solution|Solution 2.6}}
    71: ...h>\text{1}\textrm{.}\text{73}\times \text{1}{{0}^{6}}</math> m. Determine the acceleration due to gra...
    100: The mass of Mars is <math>\text{6}\textrm{.}\text{42}\times \text{1}{{0}^{23}}</mat...
  5. 5. Forces and equilibrium (5,636 bytes)
    5: {{Not selected tab|[[5. Exercises|Exercises]]}}
    38: & {{T}_{1}}\cos 60{}^\circ ={{T}_{2}}\cos 60{}^\circ \\ & {{T}_{1}}={{T}_{2}}
    43: <math>{{T}_{1}}\sin 60{}^\circ +{{T}_{2}}\sin 60{}^\circ =2940 \ \text{N}</math>
    51: & {{T}_{1}}\sin 60{}^\circ +{{T}_{2}}\sin 60{}^\circ =2940 \\
    52: & 2{{T}_{1}}\sin 60{}^\circ =2940 \\
  6. 6. Kinematics in one dimension (6,592 bytes)
    4: {{Selected tab|[[6. Kinematics in one dimension|Theory]]}}
    5: {{Not selected tab|[[6. Exercises|Exercises]]}}
    6: {{Not selected tab|[[6. Video|Video]]}}
    53: '''[[Example 6.1]]'''
    62: [[Image:ex6.1fig1test1.gif]]
  7. 7. Position Vectors (4,271 bytes)
    5: {{Not selected tab|[[7. Exercises|Exercises]]}}
    46: <math>{{\mathbf{r}}_{B}}=(6t-{{t}^{2}})\mathbf{i}+t\mathbf{j}</math>
    66: | valign="top"|<math>{{\mathbf{r}}_{B}}=(6\times 0-{{0}^{2}})\mathbf{i}+0\mathbf{j}=0\mathbf...
    70: |valign="top"| <math>{{\mathbf{r}}_{B}}=(6\times 1-{{1}^{2}})\mathbf{i}+1\mathbf{j}=5\mathbf...
    74: |valign="top"|<math>{{\mathbf{r}}_{B}}=(6\times 2-{{2}^{2}})\mathbf{i}+2\mathbf{j}=8\mathbf...
  8. 8. Constant acceleration equations in vector form (8,382 bytes)
    5: {{Not selected tab|[[8. Exercises|Exercises]]}}
    39: (6
    55: <math>\mathbf{v}=6\mathbf{i}-5\mathbf{j}</math>
    65: & 6\mathbf{i}-5\mathbf{j}=8\mathbf{i}+12\mathbf{j}+20...
    173: & =6\textrm{.}264\mathbf{i}+0\mathbf{j} \\
  9. 9. Newton’s first law (2,611 bytes)
    5: {{Not selected tab|[[9. Exercises|Exercises]]}}
    39: The lift force is 8624 N.
    41: ...ending at a constant rate the lift force will be 8624 N.
    61: <math>P=735\sin 6{}^\circ =76\textrm{.}8\text{ N}</math>
    66: A skier, of mass 60 kg, skis down a slope inclined at to the horiz...
  10. 10. Newton’s second law (5,608 bytes)
    5: {{Not selected tab|[[10. Exercises|Exercises]]}}
    102: & R=3000-2160 \\
    153: Resultant Force <math>=11760\sin 3{}^\circ -400</math>
    160: & 11760\sin 3{}^\circ -400=1200a \\
    161: & a=\frac{11760\sin 3{}^\circ -400}{1200}=0\textrm{.}180\text{ m...
  11. 11. Newton’s third law (1,707 bytes)
    5: {{Not selected tab|[[11. Exercises|Exercises]]}}
  12. 3. Exercises (5,734 bytes)
    5: {{Selected tab|[[3. Exercises|Exercises]]}}
    61: ===Exercise 3.6===
    72: ...nswer 3.6a|Answer b|Answer 3.6b|Answer c|Answer 3.6c}}
    100: ...tude of the friction force on the box if <math>P=760\text{ N}</math>.
    167: ... of friction between the tank and the ground is 0.6. The rope exerts a horizontal force of magnitude ...
  13. 4. Exercises (4,452 bytes)
    5: {{Selected tab|[[4. Exercises|Exercises]]}}
    42: 6 <math>\mathbf{i}</math><math>+</math>8
    90: ===Exercise 4.6===
    95: [[Image:E4.6.GIF]]
    103: ...6a|Solution b|Solution 4.6b|Solution c|Solution 4.6c}}
  14. 5. Exercises (4,879 bytes)
    5: {{Selected tab|[[5. Exercises|Exercises]]}}
    101: ===Exercise 5.6===
    113: ...r 5.6b|Answer c|Answer 5.6c|Solution c|Solution 5.6c}}
  15. 6. Exercises (5,072 bytes)
    4: {{Not selected tab|[[6. Kinematics in one dimension|Theory]]}}
    5: {{Selected tab|[[6. Exercises|Exercises]]}}
    6: {{Not selected tab|[[6. Video|Video]]}}
    10: ===Exercise 6.1===
    15: [[Image:E6.1.GIF]]
  16. 7. Exercises (3,029 bytes)
    5: {{Selected tab|[[7. Exercises|Exercises]]}}
    15: <math>\mathbf{r}=6t\mathbf{i}+\left( 15t-4\textrm{.}9{{t}^{2}} \righ...
    62: <math>\mathbf{r}=(2t-16)\mathbf{i}+(4t-12)\mathbf{j}</math>
  17. 8. Exercises (8,050 bytes)
    5: {{Selected tab|[[8. Exercises|Exercises]]}}
    51: ...> and is at the point with position vector (<math>6\mathbf{i}+2\mathbf{j}</math>) m.
    57: ... of the particle (<math>4\textrm{.}8\mathbf{i}– 6\textrm{.}8\mathbf{j}</math>) <math>\text{m}{{\te...
    77: ===Exercise 8.6===
    81: ...h> until after 10 seconds its velocity is (<math>6\mathbf{i}-8\mathbf{j}</math>) <math>\text{m}{{\...
  18. 9. Exercises (2,456 bytes)
    5: {{Selected tab|[[9. Exercises|Exercises]]}}
    47: A skier of mass 60 kg is travelling at a constant speed down a slop...
    52: ===Exercise 9.6===
    55: A car of mass 1600 kg is towed up a hill of inclined at 5<math>{}^...
    57: [[Image:E9.6.GIF]]
  19. 10. Exercises (2,954 bytes)
    5: {{Selected tab|[[10. Exercises|Exercises]]}}
    44: A particle of mass 6 kg starts from rest and accelerates uniformly. Th...
    56: ===Exercise 10.6===
    61: ...AVCONTENT:Answer|Answer 10.6|Solution|Solution 10.6}}
  20. 11. Exercises (1,991 bytes)
    5: {{Selected tab|[[11. Exercises|Exercises]]}}

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