Lösning 1.2.3a
Förberedande kurs i matematik
(Skillnad mellan versioner)
(3 mellanliggande versioner visas inte.) | |||
Rad 1: | Rad 1: | ||
- | <math>2^{2+1}+3^{6/2}+(2+3)^3+3444^{7^0}=2^3+3^3+5^3+3444^{1}=\\ | + | <math>\begin{align}2^{2+1}+3^{6/2}+(2+3)^3+3444^{7^0}&=2^3+3^3+5^3+3444^{1}=\\&=8+27+125+3444=\\&=3604\end{align}</math> |
- | =8+27+125+3444=3604</math> | + |
Nuvarande version
\displaystyle \begin{align}2^{2+1}+3^{6/2}+(2+3)^3+3444^{7^0}&=2^3+3^3+5^3+3444^{1}=\\&=8+27+125+3444=\\&=3604\end{align}