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Förklaring 3.3:3

Skriv \displaystyle \tfrac{1}{8} som \displaystyle 8^{-1} och använd logaritmlagarna,

\displaystyle \log_8 \tfrac{1}{8} = \log_8 8^{-1} = (-1)\log_8 8 = (-1)\cdot 1 = -1\textrm{.}