Lösung 3.2:6b
Aus Online Mathematik Brückenkurs 2
(Unterschied zwischen Versionen)
K (Lösning 3.2:6b moved to Solution 3.2:6b: Robot: moved page) |
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- | + | If we determine the number's magnitude | |
- | < | + | <math>r</math> |
- | + | and argument | |
+ | <math>\alpha </math>, we can write its polar form using the formula | ||
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+ | <math>r\left( \cos \alpha +i\sin \alpha \right)</math> | ||
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+ | Because the number lies on the imaginary axis, it is possible to write its magnitude and argument directly: | ||
[[Image:3_2_6_b.gif|center]] | [[Image:3_2_6_b.gif|center]] | ||
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+ | The polar form is | ||
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+ | <math>11\left( \cos \frac{3\pi }{2}+i\sin \frac{3\pi }{2} \right)</math>. |
Version vom 10:17, 23. Okt. 2008
If we determine the number's magnitude \displaystyle r and argument \displaystyle \alpha , we can write its polar form using the formula
\displaystyle r\left( \cos \alpha +i\sin \alpha \right)
Because the number lies on the imaginary axis, it is possible to write its magnitude and argument directly:
The polar form is
\displaystyle 11\left( \cos \frac{3\pi }{2}+i\sin \frac{3\pi }{2} \right).