Lösung 3.2:6b

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If we determine the number's magnitude
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If we determine the number's magnitude <math>r</math> and argument <math>\alpha </math>, we can write its polar form using the formula
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<math>r</math>
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and argument
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<math>\alpha </math>, we can write its polar form using the formula
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{{Displayed math||<math>r(\cos\alpha + i\sin\alpha)\,\textrm{.}</math>}}
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<math>r\left( \cos \alpha +i\sin \alpha \right)</math>
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Because the number lies on the imaginary axis, it is possible to write its magnitude and argument directly.
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Because the number lies on the imaginary axis, it is possible to write its magnitude and argument directly:
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[[Image:3_2_6_b.gif|center]]
[[Image:3_2_6_b.gif|center]]
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The polar form is
The polar form is
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{{Displayed math||<math>11\Bigl(\cos\frac{3\pi}{2} + i\sin\frac{3\pi}{2}\Bigr)\,\textrm{.}</math>}}
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<math>11\left( \cos \frac{3\pi }{2}+i\sin \frac{3\pi }{2} \right)</math>.
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Version vom 13:14, 29. Okt. 2008

If we determine the number's magnitude \displaystyle r and argument \displaystyle \alpha , we can write its polar form using the formula

\displaystyle r(\cos\alpha + i\sin\alpha)\,\textrm{.}

Because the number lies on the imaginary axis, it is possible to write its magnitude and argument directly.

The polar form is

\displaystyle 11\Bigl(\cos\frac{3\pi}{2} + i\sin\frac{3\pi}{2}\Bigr)\,\textrm{.}
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_3.2:6b“