Svar 5.1:3
Förberedande kurs i matematik 1
| a) | \displaystyle\frac{x+1}{x^2-1} = \displaystyle\frac{1}{x-1} |
| b) | \left(\displaystyle\frac{5}{x}-1\right)(1-x) |
| c) | \displaystyle\frac{\frac{1}{2}}{\frac{1}{3}+\frac{1}{4}} |
| d) | \displaystyle\frac{1}{1+\displaystyle\frac{1}{1+x}} |
