Lösning till övning 3

SamverkanLinalgLIU

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<center><math>\boldsymbol{u}+\boldsymbol{v}=\underline{\boldsymbol{e}}\begin{pmatrix}{a_1}\\{b_1}\\{c_1}\end{pmatrix}+\underline{\boldsymbol{e}}\begin{pmatrix}{a_2}\\{b_2}\\{c_2}\end{pmatrix}=\underline{\boldsymbol{e}}\begin{pmatrix}{a_1+a_2}\\{b_1+b_2}\\{c_1+c_2}\end{pmatrix}</center></math>
<center><math>\boldsymbol{u}+\boldsymbol{v}=\underline{\boldsymbol{e}}\begin{pmatrix}{a_1}\\{b_1}\\{c_1}\end{pmatrix}+\underline{\boldsymbol{e}}\begin{pmatrix}{a_2}\\{b_2}\\{c_2}\end{pmatrix}=\underline{\boldsymbol{e}}\begin{pmatrix}{a_1+a_2}\\{b_1+b_2}\\{c_1+c_2}\end{pmatrix}</center></math>
och
och
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<center><math>\lambda\boldsymbol{u}=\lambda\underline{\boldsymbol{e}}\begin{pmatrix}{a_1}\\{b_1}\\{c_1}\end{pmatrix}=\underline{\boldsymbol{e}}\begin{pmatrix}{\lambda a_1}\\{\lambda b_1}\\{\lambda c_1}\end{pmatrix}.</center></math>
+
<math>\lambda\boldsymbol{u}=\lambda\underline{\boldsymbol{e}}\begin{pmatrix}{a_1}\\{b_1}\\{c_1}\end{pmatrix}=\underline{\boldsymbol{e}}\begin{pmatrix}{\lambda a_1}\\{\lambda b_1}\\{\lambda c_1}\end{pmatrix}.</math>

Versionen från 14 augusti 2008 kl. 19.09

Låt \displaystyle \boldsymbol{u}=\underline{\boldsymbol{e}}X_1=\underline{\boldsymbol{e}}\begin{pmatrix}{a_1}\\{b_1}\\{c_1}\end{pmatrix} och \displaystyle \boldsymbol{v}=\underline{\boldsymbol{e}}X_2=\underline{\boldsymbol{e}}\begin{pmatrix}{a_2}\\{b_2}\\{c_2}\end{pmatrix}. Vi behöver summan

\displaystyle \boldsymbol{u}+\boldsymbol{v}=\underline{\boldsymbol{e}}\begin{pmatrix}{a_1}\\{b_1}\\{c_1}\end{pmatrix}+\underline{\boldsymbol{e}}\begin{pmatrix}{a_2}\\{b_2}\\{c_2}\end{pmatrix}=\underline{\boldsymbol{e}}\begin{pmatrix}{a_1+a_2}\\{b_1+b_2}\\{c_1+c_2}\end{pmatrix}

och

\displaystyle \lambda\boldsymbol{u}=\lambda\underline{\boldsymbol{e}}\begin{pmatrix}{a_1}\\{b_1}\\{c_1}\end{pmatrix}=\underline{\boldsymbol{e}}\begin{pmatrix}{\lambda a_1}\\{\lambda b_1}\\{\lambda c_1}\end{pmatrix}.