Svar 5.1:4
Förberedande kurs i matematik 1
(Skillnad mellan versioner)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="100%" | \sin^2 x+\cos x |- |b) |width="100%" | \cos v=\cos\dfrac{3\pi}{2} |- |c) |width="100%" | \cot 2x=\dfrac{1}{\tan 2x} |- |d) |width="100...) |
(\dfrac --> \displaystyle\frac) |
||
Rad 4: | Rad 4: | ||
|- | |- | ||
|b) | |b) | ||
- | |width="100%" | \cos v=\cos\ | + | |width="100%" | \cos v=\cos\displaystyle\frac{3\pi}{2} |
|- | |- | ||
|c) | |c) | ||
- | |width="100%" | \cot 2x=\ | + | |width="100%" | \cot 2x=\displaystyle\frac{1}{\tan 2x} |
|- | |- | ||
|d) | |d) | ||
- | |width="100%" | \tan\ | + | |width="100%" | \tan\displaystyle\frac{u}{2}=\displaystyle\frac{\sin u}{1+\cos u} |
|} | |} |
Nuvarande version
a) | \sin^2 x+\cos x |
b) | \cos v=\cos\displaystyle\frac{3\pi}{2} |
c) | \cot 2x=\displaystyle\frac{1}{\tan 2x} |
d) | \tan\displaystyle\frac{u}{2}=\displaystyle\frac{\sin u}{1+\cos u} |