Svar 5.1:4

Förberedande kurs i matematik 1

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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="100%" | \sin^2 x+\cos x |- |b) |width="100%" | \cos v=\cos\dfrac{3\pi}{2} |- |c) |width="100%" | \cot 2x=\dfrac{1}{\tan 2x} |- |d) |width="100...)
Nuvarande version (3 juli 2009 kl. 13.29) (redigera) (ogör)
(\dfrac --> \displaystyle\frac)
 
Rad 4: Rad 4:
|-
|-
|b)
|b)
-
|width="100%" | \cos v=\cos\dfrac{3\pi}{2}
+
|width="100%" | \cos v=\cos\displaystyle\frac{3\pi}{2}
|-
|-
|c)
|c)
-
|width="100%" | \cot 2x=\dfrac{1}{\tan 2x}
+
|width="100%" | \cot 2x=\displaystyle\frac{1}{\tan 2x}
|-
|-
|d)
|d)
-
|width="100%" | \tan\dfrac{u}{2}=\dfrac{\sin u}{1+\cos u}
+
|width="100%" | \tan\displaystyle\frac{u}{2}=\displaystyle\frac{\sin u}{1+\cos u}
|}
|}

Nuvarande version

a) \sin^2 x+\cos x
b) \cos v=\cos\displaystyle\frac{3\pi}{2}
c) \cot 2x=\displaystyle\frac{1}{\tan 2x}
d) \tan\displaystyle\frac{u}{2}=\displaystyle\frac{\sin u}{1+\cos u}