Förberedande Mekanik

Time	Position of A (rA)	Position of B (rB)
0	\displaystyle {{\mathbf{r}}_{A}}=0\mathbf{i}+0\mathbf{j}	\displaystyle {{\mathbf{r}}_{B}}=(6\times 0-{{0}^{2}})\mathbf{i}+0\mathbf{j}=0\mathbf{i}+0\mathbf{j}
1	\displaystyle {{\mathbf{r}}_{A}}=2\mathbf{i}+1\mathbf{j}	\displaystyle {{\mathbf{r}}_{B}}=(6\times 1-{{1}^{2}})\mathbf{i}+1\mathbf{j}=5\mathbf{i}+1\mathbf{j}
2	\displaystyle {{\mathbf{r}}_{A}}=4\mathbf{i}+2\mathbf{j}	\displaystyle {{\mathbf{r}}_{B}}=(6\times 2-{{2}^{2}})\mathbf{i}+2\mathbf{j}=8\mathbf{i}+2\mathbf{j}
15 N	\displaystyle -15\cos 30{}^\circ \mathbf{i}+15\sin 30{}^\circ \mathbf{j}

0

1

2

3 \displaystyle {{\mathbf{r}}_{A}}=6\mathbf{i}+3\mathbf{j}

\displaystyle {{\mathbf{r}}_{B}}=(6\times 3-{{3}^{2}})\mathbf{i}+3\mathbf{j}=9\mathbf{i}+3\mathbf{j}

4 \displaystyle {{\mathbf{r}}_{A}}=8\mathbf{i}+4\mathbf{j}

\displaystyle {{\mathbf{r}}_{B}}=(6\times 4-{{4}^{2}})\mathbf{i}+4\mathbf{j}=8\mathbf{i}+4\mathbf{j}