Answer 8.5a
Förberedande Mekanik
(Skillnad mellan versioner)
(New page: <math>\mathbf{v}=(80+t)\mathbf{i}+(4t)\mathbf{j}</math> <math>\mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{2}} \right)\mathbf{i}+2{{t}^{2}}\mathbf{j}</math>) |
(New page: <math>\mathbf{v}=(80+t)\mathbf{i}+(4t)\mathbf{j}</math> <math>\mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{2}} \right)\mathbf{i}+2{{t}^{2}}\mathbf{j}</math>) |
Nuvarande version
\displaystyle \mathbf{v}=(80+t)\mathbf{i}+(4t)\mathbf{j}
\displaystyle \mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{2}} \right)\mathbf{i}+2{{t}^{2}}\mathbf{j}