Answer 8.5a

Förberedande Mekanik

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(New page: <math>\mathbf{v}=(80+t)\mathbf{i}+(4t)\mathbf{j}</math> <math>\mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{2}} \right)\mathbf{i}+2{{t}^{2}}\mathbf{j}</math>)
Nuvarande version (12 september 2009 kl. 16.28) (redigera) (ogör)
(New page: <math>\mathbf{v}=(80+t)\mathbf{i}+(4t)\mathbf{j}</math> <math>\mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{2}} \right)\mathbf{i}+2{{t}^{2}}\mathbf{j}</math>)
 

Nuvarande version

\displaystyle \mathbf{v}=(80+t)\mathbf{i}+(4t)\mathbf{j}

\displaystyle \mathbf{r}=\left( 80t+\frac{1}{2}{{t}^{2}} \right)\mathbf{i}+2{{t}^{2}}\mathbf{j}