Lösung 3.4:3

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A polynomial equation which has real coefficients always has complex conjugate roots. We can therefore say directly that the equation, in addition to the roots \displaystyle z=\text{2}i and \displaystyle z=-\text{1}+i, has roots \displaystyle z=\overline{2i}=-2i and \displaystyle z=\overline{-\text{1}+i}=-1-i. Because the equation is of degree 4, it does not have more than 4 roots.

The answer is thus


\displaystyle \left\{ \begin{array}{*{35}l} 2i \\ -2i \\ -1+i \\ -1-i \\ \end{array} \right.