Lösung 1.1:2b
Aus Online Mathematik Brückenkurs 2
The expression is a sum of two terms which we differentiate one by one:
\displaystyle \begin{align}
& {f}'\left( x \right)=\frac{d}{dx}\left( \cos x-\sin x \right) \\
& =\frac{d}{dx}\cos x-\frac{d}{dx}\sin x=-\sin x-\cos x \\
\end{align}