Antwort 1.3:3
Aus Online Mathematik Brückenkurs 2
| a) | \displaystyle x=0\, (Lokales Maxima) | b) | \displaystyle x=-\frac{1}{3}\ln\frac{5}{3}\, (Lokales Minima) |
| c) | \displaystyle x=1/e\, (Lokales Minima) | d) |
\displaystyle x=-\sqrt{\sqrt{2}-1}\, (Lokales Maxima) \displaystyle x=0\, (Lokales Minima) \displaystyle x=\sqrt{\sqrt{2}-1}\, (Lokales Maxima) |
| e) | \displaystyle x=-3\, (Lokales Minima)
\displaystyle x=-2\, (Lokales Maxima) \displaystyle x=1\, (Lokales Minima) \displaystyle x=3\, (Lokales Maxima) |
