Lösung 1.1:2b

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The expression is a sum of two terms which we differentiate one by one:


\displaystyle \begin{align} & {f}'\left( x \right)=\frac{d}{dx}\left( \cos x-\sin x \right) \\ & =\frac{d}{dx}\cos x-\frac{d}{dx}\sin x=-\sin x-\cos x \\ \end{align}