Antwort 3.3:5

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Version vom 09:14, 11. Mär. 2009

a) \displaystyle z= \left\{\begin{matrix} 2+1 \\ i \\ \end{matrix}\right. b) \displaystyle z = \left\{\begin{matrix} 1+i\phantom{2} \\ 1-2i \\ \end{matrix}\right.
c) \displaystyle z= \left\{\begin{matrix} \phantom{-}2+i\phantom{2} \\ -1+2i \\ \end{matrix}\right. d) \displaystyle z= \left\{\begin{matrix} i \\ 1+4i \\ \end{matrix}\right.