Lösung 2.1:1a

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The integral's value can be interpreted as the area under the graph
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The value of the integral can be interpreted as the area under the graph <math>y=2</math> from <math>x=-1\ </math> to <math>x=2</math>.
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<math>y=2</math>
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from
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<math>x=-1\ </math>
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to
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<math>\text{ }x=2</math>.
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[[Image:2_1_1_a.gif|center]]
[[Image:2_1_1_a.gif|center]]
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Because the region is a rectangle, we can determine its area directly and obtain
Because the region is a rectangle, we can determine its area directly and obtain
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{{Displayed math||<math>\int\limits_{-1}^{2} 2\,dx = \text{(base)}\cdot\text{(height)} = 3\cdot 2 = 6\,\textrm{.}</math>}}
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<math>\int\limits_{-1}^{2}{2dx=}</math>
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(base)
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<math>\centerdot </math>
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(height)
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<math>=3\centerdot 2=6</math>
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Version vom 12:04, 21. Okt. 2008

The value of the integral can be interpreted as the area under the graph \displaystyle y=2 from \displaystyle x=-1\ to \displaystyle x=2.

Because the region is a rectangle, we can determine its area directly and obtain

\displaystyle \int\limits_{-1}^{2} 2\,dx = \text{(base)}\cdot\text{(height)} = 3\cdot 2 = 6\,\textrm{.}
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_2.1:1a“