Antwort 3.3:2
Aus Online Mathematik Brückenkurs 2
(Unterschied zwischen Versionen)
| Zeile 5: | Zeile 5: | ||
|width="33%"| <math>z = \left\{\begin{matrix} \frac{1}{2}+\frac{1}{2}\sqrt{3}\,i \\ -1\phantom{{}-\frac{1}{2}\sqrt{3}\,i} \\ \frac{1}{2}-\frac{1}{2}\sqrt{3}\,i \\ \end{matrix}\right.</math> | |width="33%"| <math>z = \left\{\begin{matrix} \frac{1}{2}+\frac{1}{2}\sqrt{3}\,i \\ -1\phantom{{}-\frac{1}{2}\sqrt{3}\,i} \\ \frac{1}{2}-\frac{1}{2}\sqrt{3}\,i \\ \end{matrix}\right.</math> | ||
|c) | |c) | ||
| - | |width="33%"| <math>\displaystyle z=2^{1/10}\exp\Bigl(\frac{\pi i}{4}+\frac{2k\pi i}{5}\Bigr)</math> | + | |width="33%"| <math>\displaystyle z=2^{1/10}\exp\Bigl(\frac{\pi i}{4}+\frac{2k\pi i}{5}\Bigr)</math> for <math>\ k=0,1,2,3,4</math> |
|- | |- | ||
|d) | |d) | ||
Version vom 14:30, 5. Sep. 2008
| a) | \displaystyle z= \left\{\begin{matrix} \phantom{-}1 \\ -1 \\ \phantom{-}i \\ -i\\ \end{matrix}\right. | b) | \displaystyle z = \left\{\begin{matrix} \frac{1}{2}+\frac{1}{2}\sqrt{3}\,i \\ -1\phantom{{}-\frac{1}{2}\sqrt{3}\,i} \\ \frac{1}{2}-\frac{1}{2}\sqrt{3}\,i \\ \end{matrix}\right. | c) | \displaystyle \displaystyle z=2^{1/10}\exp\Bigl(\frac{\pi i}{4}+\frac{2k\pi i}{5}\Bigr) for \displaystyle \ k=0,1,2,3,4 |
| d) | \displaystyle z= \left\{\begin{matrix} 2+i \\ 2-i \\ \phantom{-}i \\ -i\\ \end{matrix}\right. | e) | \displaystyle z = \left\{\begin{matrix} \phantom{-}1 \\ -1 \end{matrix}\right. |
