Antwort 3.3:2
Aus Online Mathematik Brückenkurs 2
(Unterschied zwischen Versionen)
| Zeile 5: | Zeile 5: | ||
|width="33%"| <math>z = \left\{\begin{matrix} \frac{1}{2}+\frac{1}{2}\sqrt{3}\,i \\ -1\phantom{{}-\frac{1}{2}\sqrt{3}\,i} \\ \frac{1}{2}-\frac{1}{2}\sqrt{3}\,i \\ \end{matrix}\right.</math> | |width="33%"| <math>z = \left\{\begin{matrix} \frac{1}{2}+\frac{1}{2}\sqrt{3}\,i \\ -1\phantom{{}-\frac{1}{2}\sqrt{3}\,i} \\ \frac{1}{2}-\frac{1}{2}\sqrt{3}\,i \\ \end{matrix}\right.</math> | ||
|c) | |c) | ||
| - | |width="33%"| <math> | + | |width="33%"|<math>z= \left\{\begin{matrix} 2^{\frac{1}{10}}e^{i(\frac{\pi}{4})} \\ 2^{\frac{1}{10}}e^{i(\frac{13\pi}{20})} \\ 2^{\frac{1}{10}}e^{i(\frac{21\pi}{20})} \\ 2^{\frac{1}{10}}e^{i(\frac{29\pi}{20})}\\ 2^{\frac{1}{10}}e^{i(\frac{37\pi}{20})} \\ \end{matrix}\right.</math> |
|- | |- | ||
|d) | |d) | ||
Aktuelle Version
| a) | \displaystyle z= \left\{\begin{matrix} \phantom{-}1 \\ -1 \\ \phantom{-}i \\ -i\\ \end{matrix}\right. | b) | \displaystyle z = \left\{\begin{matrix} \frac{1}{2}+\frac{1}{2}\sqrt{3}\,i \\ -1\phantom{{}-\frac{1}{2}\sqrt{3}\,i} \\ \frac{1}{2}-\frac{1}{2}\sqrt{3}\,i \\ \end{matrix}\right. | c) | \displaystyle z= \left\{\begin{matrix} 2^{\frac{1}{10}}e^{i(\frac{\pi}{4})} \\ 2^{\frac{1}{10}}e^{i(\frac{13\pi}{20})} \\ 2^{\frac{1}{10}}e^{i(\frac{21\pi}{20})} \\ 2^{\frac{1}{10}}e^{i(\frac{29\pi}{20})}\\ 2^{\frac{1}{10}}e^{i(\frac{37\pi}{20})} \\ \end{matrix}\right. |
| d) | \displaystyle z= \left\{\begin{matrix} 2+i \\ 2-i \\ \phantom{-}i \\ -i\\ \end{matrix}\right. | e) | \displaystyle z = \left\{\begin{matrix} \phantom{-}1 \\ -1 \end{matrix}\right. |
