Antwort 2.3:1
Aus Online Mathematik Brückenkurs 2
(Unterschied zwischen Versionen)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"|<math>-2(x+1)e^{-x}+C</math> |b) |width="50%"| <math>-(x+1)\cos x+\sin x + C</math> |- |c) |width="50%"| <math>2x\cos x + (x^2-2)\sin x +...) |
K (Svar 2.3:1 moved to Answer 2.3:1: Robot: moved page) |
Version vom 14:03, 16. Sep. 2008
| a) | \displaystyle -2(x+1)e^{-x}+C | b) | \displaystyle -(x+1)\cos x+\sin x + C |
| c) | \displaystyle 2x\cos x + (x^2-2)\sin x + C | d) | \displaystyle \displaystyle\frac{x^2}{2}\left(\ln x - \frac{1}{2}\right) + C |
