Antwort 2.1:2

Aus Online Mathematik Brückenkurs 2

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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"|<math>\displaystyle\int_{0}^{2} (x^2+3x^3)\, dx</math> |b) |width="50%"| <math>\displaystyle\int_{-1}^{2} (x-2)(x+1)\, dx</math> |- |c) |...)
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{| width="100%" cellspacing="10px"
{| width="100%" cellspacing="10px"
|a)
|a)
-
|width="50%"|<math>\displaystyle\int_{0}^{2} (x^2+3x^3)\, dx</math>
+
|width="50%"|<math>\displaystyle\frac{44}{3}</math>
|b)
|b)
-
|width="50%"| <math>\displaystyle\int_{-1}^{2} (x-2)(x+1)\, dx</math>
+
|width="50%"| <math>\displaystyle-\frac{9}{2}</math>
|-
|-
|c)
|c)
-
|width="50%"| <math> \displaystyle\int_{4}^{9} \left(\sqrt{x} - \displaystyle\frac{1}{\sqrt{x}}\right)\, dx</math>
+
|width="50%"| <math>\displaystyle\frac{32}{3}</math>
|d)
|d)
-
|width="50%"| <math>\displaystyle\int_{1}^{4} \displaystyle\frac{\sqrt{x}}{x^2}\, dx</math>
+
|width="50%"| <math>1</math>
|}
|}

Version vom 07:33, 7. Apr. 2008

a) \displaystyle \displaystyle\frac{44}{3} b) \displaystyle \displaystyle-\frac{9}{2}
c) \displaystyle \displaystyle\frac{32}{3} d) \displaystyle 1
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/Antwort_2.1:2“