Antwort 2.2:1

Aus Online Mathematik Brückenkurs 2

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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"|<math>\displaystyle\frac{44}{3}</math> |b) |width="50%"| <math>\displaystyle-\frac{9}{2}</math> |- |c) |width="50%"| <math> \displaystyle...)
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{| width="100%" cellspacing="10px"
{| width="100%" cellspacing="10px"
|a)
|a)
-
|width="50%"|<math>\displaystyle\frac{44}{3}</math>
+
|width="100%"|<math>\displaystyle\frac{13}{1000}</math>
 +
|-
|b)
|b)
-
|width="50%"| <math>\displaystyle-\frac{9}{2}</math>
+
|width="100%"| <math>\displaystyle\frac{(x^2+3)^6}{12}+C</math>
|-
|-
|c)
|c)
-
|width="50%"| <math> \displaystyle\frac{32}{3}</math>
+
|width="100%"| <math>\displaystyle\frac{1}{3}e^{\scriptstyle x^3}+C</math>
-
|d)
+
-
|width="50%"| <math>1</math>
+
|}
|}

Version vom 08:53, 7. Apr. 2008

a) \displaystyle \displaystyle\frac{13}{1000}
b) \displaystyle \displaystyle\frac{(x^2+3)^6}{12}+C
c) \displaystyle \displaystyle\frac{1}{3}e^{\scriptstyle x^3}+C
Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/Antwort_2.2:1“