Lösung 3.4:7b
Aus Online Mathematik Brückenkurs 2
(Unterschied zwischen Versionen)
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According to the factor theorem, a polynomial that has the zeros <math>-1+i</math> and <math>-1-i</math> must contain the factors <math>z-(-1+i)</math> and <math>z-(-1-i)</math>. An example of such a polynomial is | According to the factor theorem, a polynomial that has the zeros <math>-1+i</math> and <math>-1-i</math> must contain the factors <math>z-(-1+i)</math> and <math>z-(-1-i)</math>. An example of such a polynomial is | ||
- | {{ | + | {{Abgesetzte Formel||<math>(z-(-1+i))(z-(-1-i)) = z^2+2z+2\,\textrm{.}</math>}} |
Note: If one wants to have all the polynomials which have only these zeros, the answer is | Note: If one wants to have all the polynomials which have only these zeros, the answer is | ||
- | {{ | + | {{Abgesetzte Formel||<math>C(z+1-i)^m(z+1+i)^n</math>}} |
where <math>C</math> is a non-zero constant and <math>m</math> and <math>n</math> are positive integers. | where <math>C</math> is a non-zero constant and <math>m</math> and <math>n</math> are positive integers. |
Version vom 13:16, 10. Mär. 2009
According to the factor theorem, a polynomial that has the zeros \displaystyle -1+i and \displaystyle -1-i must contain the factors \displaystyle z-(-1+i) and \displaystyle z-(-1-i). An example of such a polynomial is
\displaystyle (z-(-1+i))(z-(-1-i)) = z^2+2z+2\,\textrm{.} |
Note: If one wants to have all the polynomials which have only these zeros, the answer is
\displaystyle C(z+1-i)^m(z+1+i)^n |
where \displaystyle C is a non-zero constant and \displaystyle m and \displaystyle n are positive integers.