Lösung 3.2:1d
Aus Online Mathematik Brückenkurs 2
(Unterschied zwischen Versionen)
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If we calculate the expression, we get the answer at once, | If we calculate the expression, we get the answer at once, | ||
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z-\bar{w}+u | z-\bar{w}+u | ||
&= (2+i)-(2-3i)+(-1-2i)\\[5pt] | &= (2+i)-(2-3i)+(-1-2i)\\[5pt] | ||
Version vom 13:07, 10. Mär. 2009
If we calculate the expression, we get the answer at once,
| \displaystyle \begin{align}
z-\bar{w}+u &= (2+i)-(2-3i)+(-1-2i)\\[5pt] &= 2-2-1+(1+3-2)i\\[5pt] &= -1+2i\,\textrm{.} \end{align} |
If, on the other hand, we interpret the expression in terms of vectors, we must first understand the vector \displaystyle \bar{w} geometrically. When we take the complex conjugate of \displaystyle w, we change the sign of the imaginary part, which is the same as reflecting \displaystyle w in the real axis.
We can then construct the expression \displaystyle z-\bar{w}+u one term at a time.
