Antwort 1.2:4

Aus Online Mathematik Brückenkurs 2

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(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%"| <math>\displaystyle\frac{3x}{(1-x^2)^{5/2}}</math> |b) |width="33%"| <math>\displaystyle - \frac{2\sin \ln x}{x}</math> |})
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{| width="100%" cellspacing="10px"
{| width="100%" cellspacing="10px"
|a)
|a)
-
|width="33%"| <math>\displaystyle\frac{3x}{(1-x^2)^{5/2}}</math>
+
|width="50%"| <math>\displaystyle\frac{3x}{(1-x^2)^{5/2}}</math>
|b)
|b)
-
|width="33%"| <math>\displaystyle - \frac{2\sin \ln x}{x}</math>
+
|width="50%"| <math>\displaystyle - \frac{2\sin \ln x}{x}</math>
|}
|}

Version vom 08:16, 8. Mai 2008

a) \displaystyle \displaystyle\frac{3x}{(1-x^2)^{5/2}} b) \displaystyle \displaystyle - \frac{2\sin \ln x}{x}