Lösung 1.2:1e
Aus Online Mathematik Brückenkurs 2
(Unterschied zwischen Versionen)
K (Lösning 1.2:1e moved to Solution 1.2:1e: Robot: moved page) |
Version vom 14:23, 16. Sep. 2008
The quotient rule gives
\displaystyle \begin{align}
& \left( \frac{x}{\ln x} \right)^{\prime }=\frac{\left( x \right)^{\prime }\centerdot \ln x-x\centerdot \left( \ln x \right)^{\prime }}{\left( \ln x \right)^{2}} \\
& \\
& =\frac{1\centerdot \ln x-x\centerdot \frac{1}{x}}{\left( \ln x \right)^{2}}=\frac{\ln x-1}{\left( \ln x \right)^{2}}=\frac{1}{\ln x}-\frac{1}{\left( \ln x \right)^{2}} \\
\end{align}
