Antwort 2.2:1
Aus Online Mathematik Brückenkurs 2
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K (Svar 2.2:1 moved to Answer 2.2:1: Robot: moved page) |
K (Answer 2.2:1 moved to Antwort 2.2:1: Robot: moved page) |
Aktuelle Version
a) | \displaystyle \displaystyle\frac{13}{1000} |
b) | \displaystyle \displaystyle\frac{(x^2+3)^6}{12}+C |
c) | \displaystyle \displaystyle\frac{1}{3}e^{\scriptstyle x^3}+C |