Antwort 2.1:3
Aus Online Mathematik Brückenkurs 2
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K (Svar 2.1:3 moved to Answer 2.1:3: Robot: moved page) |
K (Answer 2.1:3 moved to Antwort 2.1:3: Robot: moved page) |
Aktuelle Version
a) | \displaystyle -\cos x + C | b) | \displaystyle \displaystyle-\frac{\cos 2x}{2}+C |
c) | \displaystyle \displaystyle\frac{e^{3x}}{3}+\frac{e^{2x}}{2}+C | d) | \displaystyle \displaystyle\frac{x^2}{2}+\ln x + C |