Antwort 2.3:2
Aus Online Mathematik Brückenkurs 2
(Unterschied zwischen Versionen)
K (Answer 2.3:2 moved to Antwort 2.3:2: Robot: moved page) |
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|width="50%"| <math>-\ln|\cos x|+C</math> | |width="50%"| <math>-\ln|\cos x|+C</math> | ||
|d) | |d) | ||
- | |width="50%"| <math>x(\ln x-1)+C</math> | + | |width="50%"| <math>x\,(\ln x-1)+C</math> |
|} | |} |
Aktuelle Version
a) | \displaystyle 2e^{\sqrt{x}}\left(\sqrt{x}-1\right)+C | b) | \displaystyle \displaystyle\frac{1}{2} |
c) | \displaystyle -\ln|\cos x|+C | d) | \displaystyle x\,(\ln x-1)+C |