Antwort 2.3:1
Aus Online Mathematik Brückenkurs 2
(Unterschied zwischen Versionen)
K (Svar 2.3:1 moved to Answer 2.3:1: Robot: moved page) |
K (Answer 2.3:1 moved to Antwort 2.3:1: Robot: moved page) |
Aktuelle Version
| a) | \displaystyle -2(x+1)e^{-x}+C | b) | \displaystyle -(x+1)\cos x+\sin x + C |
| c) | \displaystyle 2x\cos x + (x^2-2)\sin x + C | d) | \displaystyle \displaystyle\frac{x^2}{2}\left(\ln x - \frac{1}{2}\right) + C |
