Lösung 2.1:1a

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{{NAVCONTENT_START}}
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The integral's value can be interpreted as the area under the graph
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<center> [[Image:2_1_1a.gif]] </center>
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<math>y=2</math>
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{{NAVCONTENT_STOP}}
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from
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<math>x=-1\ </math>
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to
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<math>\text{ }x=2</math>.
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[[Image:2_1_1_a.gif|center]]
[[Image:2_1_1_a.gif|center]]
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Because the region is a rectangle, we can determine its area directly and obtain
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<math>\int\limits_{-1}^{2}{2dx=}</math>
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(base)
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<math>\centerdot </math>
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(height)
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<math>=3\centerdot 2=6</math>

Version vom 11:29, 17. Okt. 2008

The integral's value can be interpreted as the area under the graph \displaystyle y=2 from \displaystyle x=-1\ to \displaystyle \text{ }x=2.


Because the region is a rectangle, we can determine its area directly and obtain


\displaystyle \int\limits_{-1}^{2}{2dx=} (base) \displaystyle \centerdot (height) \displaystyle =3\centerdot 2=6

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse2-TU-Berlin/index.php/L%C3%B6sung_2.1:1a“