Antwort 1.3:2

Aus Online Mathematik Brückenkurs 2

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{| width="100%" cellspacing="10px"
{| width="100%" cellspacing="10px"
|a)
|a)
-
|width="50%"| <math>x=1\,</math> (lokal minimipunkt)
+
|width="50%"| <math>x=1\,</math> (local minima)
|b)
|b)
-
|width="50%"| <math>x=\frac{3}{2}\,</math> (lokal maximipunkt)
+
|width="50%"| <math>x=\frac{3}{2}\,</math> (local maxima)
|-
|-
|c)
|c)
-
|width="50%"| <math>x=-2\,</math> (lokal maximipunkt)
+
|width="50%"| <math>x=-2\,</math> (local maxima)
-
<math>x=1\,</math> (lokal minimipunkt)
+
<math>x=1\,</math> (local minima)
|d)
|d)
-
|width="50%"| lokal extrempunkt saknas
+
|width="50%"| no local extrema
|}
|}

Version vom 07:22, 3. Sep. 2008

a) \displaystyle x=1\, (local minima) b) \displaystyle x=\frac{3}{2}\, (local maxima)
c) \displaystyle x=-2\, (local maxima)

\displaystyle x=1\, (local minima)

d) no local extrema