Aus Online Mathematik Brückenkurs 1

Version vom 13:10, 24. Sep. 2008 (bearbeiten) Tek (Diskussion | Beiträge) K ← Zum vorherigen Versionsunterschied		Version vom 08:29, 22. Okt. 2008 (bearbeiten) (rückgängig) Tekbot (Diskussion | Beiträge) K (Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel)) Zum nächsten Versionsunterschied →
Zeile 1:		Zeile 1:
	The point of intersection is that point which satisfies the equations of both lines		The point of intersection is that point which satisfies the equations of both lines
-	{{Displayed math||<math>4x+5y+6=0\qquad\text{and}\qquad x=0\,\textrm{.}</math>}}	+	{{Abgesetzte Formel||<math>4x+5y+6=0\qquad\text{and}\qquad x=0\,\textrm{.}</math>}}
	Substituting <math>x=0</math> into <math>4x+5y+6=0</math> gives		Substituting <math>x=0</math> into <math>4x+5y+6=0</math> gives
-	{{Displayed math||<math>4\cdot 0+5y+6=0\quad\Leftrightarrow\quad y=-\frac{6}{5}\,\textrm{.}</math>}}	+	{{Abgesetzte Formel||<math>4\cdot 0+5y+6=0\quad\Leftrightarrow\quad y=-\frac{6}{5}\,\textrm{.}</math>}}
	This gives the point of intersection as <math>\bigl(0,-\tfrac{6}{5}\bigr)</math>.		This gives the point of intersection as <math>\bigl(0,-\tfrac{6}{5}\bigr)</math>.

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Version vom 08:29, 22. Okt. 2008

The point of intersection is that point which satisfies the equations of both lines

\displaystyle 4x+5y+6=0\qquad\text{and}\qquad x=0\,\textrm{.}

Substituting \displaystyle x=0 into \displaystyle 4x+5y+6=0 gives

\displaystyle 4\cdot 0+5y+6=0\quad\Leftrightarrow\quad y=-\frac{6}{5}\,\textrm{.}

This gives the point of intersection as \displaystyle \bigl(0,-\tfrac{6}{5}\bigr).