Lösung 2.2:6c

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The point of intersection is that point which satisfies the equations of both lines
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<math>4x+5y+6=0</math>
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and
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<math>x=0</math>.
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Substituting
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<math>4x+5y+6=0</math>
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into
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<math>x=0</math>
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gives
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<math>4\centerdot 0+5y+6=0\ \Leftrightarrow \ y=-\frac{6}{5}</math>
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This gives the point of intersection as
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<math>\left( 0 \right.,\left. -\frac{6}{5} \right)</math>.
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Version vom 11:34, 18. Sep. 2008

The point of intersection is that point which satisfies the equations of both lines


\displaystyle 4x+5y+6=0 and \displaystyle x=0.

Substituting \displaystyle 4x+5y+6=0 into \displaystyle x=0 gives


\displaystyle 4\centerdot 0+5y+6=0\ \Leftrightarrow \ y=-\frac{6}{5}


This gives the point of intersection as \displaystyle \left( 0 \right.,\left. -\frac{6}{5} \right).


Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_2.2:6c“