Lösung 2.2:6c
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Version vom 13:59, 22. Okt. 2008
The point of intersection is that point which satisfies the equations of both lines
| \displaystyle 4x+5y+6=0\qquad\text{and}\qquad x=0\,\textrm{.} |
Substituting \displaystyle x=0 into \displaystyle 4x+5y+6=0 gives
| \displaystyle 4\cdot 0+5y+6=0\quad\Leftrightarrow\quad y=-\frac{6}{5}\,\textrm{.} |
This gives the point of intersection as \displaystyle \bigl(0,-\tfrac{6}{5}\bigr).
