Lösung 2.1:3c
Aus Online Mathematik Brückenkurs 1
(Unterschied zwischen Versionen)
K |
K (Robot: Automated text replacement (-{{Displayed math +{{Abgesetzte Formel)) |
||
Zeile 1: | Zeile 1: | ||
The expression can be rewritten as <math> x^2+2\cdot 3\cdot x+3^2 </math> and then we see that it can be factorized, using the squaring rule <math> x^2+2ax+a^2=(x+a)^2</math>, as | The expression can be rewritten as <math> x^2+2\cdot 3\cdot x+3^2 </math> and then we see that it can be factorized, using the squaring rule <math> x^2+2ax+a^2=(x+a)^2</math>, as | ||
- | {{ | + | {{Abgesetzte Formel||<math> x^2+6x+9 =x^2+2\cdot 3\cdot x+3^2=(x+3)^2\textrm{.}</math>}} |
Version vom 08:22, 22. Okt. 2008
The expression can be rewritten as \displaystyle x^2+2\cdot 3\cdot x+3^2 and then we see that it can be factorized, using the squaring rule \displaystyle x^2+2ax+a^2=(x+a)^2, as
\displaystyle x^2+6x+9 =x^2+2\cdot 3\cdot x+3^2=(x+3)^2\textrm{.} |