Lösung 2.1:1g

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The expression in the exercise is of the form <math> (a-b)^2 </math>, where <math> a=y^2</math> and <math> b=3x^2 </math>. With the help of the squaring rule <math> (a-b)^2 =a^2 -2ab +b^2 </math>, we have
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The expression in the exercise is of the form <math> (a-b)^2 </math>, where <math> a=y^2</math> and <math> b=3x^2 </math>. With the help of the aquaring rule <math> (a-b)^2 =a^2 -2ab +b^2 </math>, we have
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{{Displayed math||<math>\begin{align}
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(y^2-3x^3)^2 &= (y^2)^2 -2\cdot y^2\cdot 3x^3 +(3x^3)^2 \\[3pt]
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<math> \begin{align} \qquad
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&= y^{2\cdot 2} -6x^3y^2 +3^2x^{3\cdot 2}\\[3pt]
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(y^2-3x^3)^2 &= (y^2)^2 -2y^2\cdot 3x^3 +(3x^3)^2 \\
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&= y^4 -6x^3y^2 +9x^6\\[3pt]
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&= y^{2\cdot 2} -6x^3y^2 +3^2x^{3\cdot 2}\\
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&= 9x^6 -6x^3y^2 +y^4\,\textrm{.}
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&= y^4 -6x^3y^2 +9x^6\\
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\end{align}</math>}}
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&= 9x^6 -6x^3y^2 +y^4
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\end{align}
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</math>
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Version vom 07:58, 23. Sep. 2008

The expression in the exercise is of the form \displaystyle (a-b)^2 , where \displaystyle a=y^2 and \displaystyle b=3x^2 . With the help of the squaring rule \displaystyle (a-b)^2 =a^2 -2ab +b^2 , we have

Vorlage:Displayed math

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_2.1:1g“