Lösung 3.1:2d

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It is often most appropriate to get rid of the root sign and write everything in power form, and then use the power rules:
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<center> [[Image:3_1_2d.gif]] </center>
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<math>\sqrt{5\centerdot \sqrt[3]{5}}\centerdot 5=5^{{1}/{2}\;}\centerdot 5^{{1}/{3}\;}\centerdot 5^{1}=5^{{1}/{2}\;+{1}/{3}\;+1}=5^{{11}/{6}\;}</math>

Version vom 10:51, 22. Sep. 2008

It is often most appropriate to get rid of the root sign and write everything in power form, and then use the power rules:


\displaystyle \sqrt{5\centerdot \sqrt[3]{5}}\centerdot 5=5^{{1}/{2}\;}\centerdot 5^{{1}/{3}\;}\centerdot 5^{1}=5^{{1}/{2}\;+{1}/{3}\;+1}=5^{{11}/{6}\;}

Von „http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-TU-Berlin/index.php/L%C3%B6sung_3.1:2d“