Svar 2.3:1
Förberedande kurs i matematik 2
(Skillnad mellan versioner)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"|<math>-2(x+1)e^{-x}+C</math> |b) |width="50%"| <math>-(x+1)\cos x+\sin x + C</math> |- |c) |width="50%"| <math>2x\cos x + (x^2-2)\sin x +...) |
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="50%"|<math>-2(x+1)e^{-x}+C</math> |b) |width="50%"| <math>-(x+1)\cos x+\sin x + C</math> |- |c) |width="50%"| <math>2x\cos x + (x^2-2)\sin x +...) |
Nuvarande version
| a) | \displaystyle -2(x+1)e^{-x}+C | b) | \displaystyle -(x+1)\cos x+\sin x + C |
| c) | \displaystyle 2x\cos x + (x^2-2)\sin x + C | d) | \displaystyle \displaystyle\frac{x^2}{2}\left(\ln x - \frac{1}{2}\right) + C |
