Svar 3.3:2
Förberedande kurs i matematik 2
(Skillnad mellan versioner)
(Ny sida: {| width="100%" cellspacing="10px" |a) |width="33%"|<math>z= \left\{\begin{matrix} \phantom{-}1 \\ -1 \\ \phantom{-}i \\ -i\\ \end{matrix}\right.</math> |b) |width="33%"| <math>z = \left\{\...) |
|||
| Rad 5: | Rad 5: | ||
|width="33%"| <math>z = \left\{\begin{matrix} \frac{1}{2}+\frac{1}{2}\sqrt{3}\,i \\ -1\phantom{{}-\frac{1}{2}\sqrt{3}\,i} \\ \frac{1}{2}-\frac{1}{2}\sqrt{3}\,i \\ \end{matrix}\right.</math> | |width="33%"| <math>z = \left\{\begin{matrix} \frac{1}{2}+\frac{1}{2}\sqrt{3}\,i \\ -1\phantom{{}-\frac{1}{2}\sqrt{3}\,i} \\ \frac{1}{2}-\frac{1}{2}\sqrt{3}\,i \\ \end{matrix}\right.</math> | ||
|c) | |c) | ||
| - | |width="33%"| <math>\displaystyle z=2^{1/10}\exp\Bigl(\frac{\pi i}{4}+\frac{2k\pi i}{5}\Bigr) | + | |width="33%"| <math>\displaystyle z=2^{1/10}\exp\Bigl(\frac{\pi i}{4}+\frac{2k\pi i}{5}\Bigr)</math> för <math>\ k=0,1,2,3,4</math> |
|- | |- | ||
|d) | |d) | ||
Nuvarande version
| a) | \displaystyle z= \left\{\begin{matrix} \phantom{-}1 \\ -1 \\ \phantom{-}i \\ -i\\ \end{matrix}\right. | b) | \displaystyle z = \left\{\begin{matrix} \frac{1}{2}+\frac{1}{2}\sqrt{3}\,i \\ -1\phantom{{}-\frac{1}{2}\sqrt{3}\,i} \\ \frac{1}{2}-\frac{1}{2}\sqrt{3}\,i \\ \end{matrix}\right. | c) | \displaystyle \displaystyle z=2^{1/10}\exp\Bigl(\frac{\pi i}{4}+\frac{2k\pi i}{5}\Bigr) för \displaystyle \ k=0,1,2,3,4 |
| d) | \displaystyle z= \left\{\begin{matrix} 2+i \\ 2-i \\ \phantom{-}i \\ -i\\ \end{matrix}\right. | e) | \displaystyle z = \left\{\begin{matrix} \phantom{-}1 \\ -1 \end{matrix}\right. |
