Solution 2.1:2e

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
Current revision (08:24, 23 September 2008) (edit) (undo)
m
 
(2 intermediate revisions not shown.)
Line 1: Line 1:
-
{{NAVCONTENT_START}}
+
We expand the two quadratics using the squaring rule, and then sum the result
-
We expand the two quadratics using the squaring rule, and then sum the result.
+
-
<math> \qquad \begin{align}(a+b)^2+(a-b)^2 &= (a^2+2ab+b^2)+(a^2-2ab+b^2)\\
+
{{Displayed math||<math>\begin{align}
 +
(a+b)^2+(a-b)^2 &= (a^2+2ab+b^2)+(a^2-2ab+b^2)\\
&= a^2+2ab+b^2+a^2-2ab+b^2 \\
&= a^2+2ab+b^2+a^2-2ab+b^2 \\
&= a^2+a^2+2ab-2ab+b^2+b^2\\
&= a^2+a^2+2ab-2ab+b^2+b^2\\
-
&= 2a^2 +2b^2
+
&= 2a^2 +2b^2\,\textrm{.}
-
\end{align}
+
\end{align}</math>}}
-
</math>
+
-
<!--<center> [[Bild:2_1_2e.gif]] </center>-->
+
-
{{NAVCONTENT_STOP}}
+

Current revision

We expand the two quadratics using the squaring rule, and then sum the result

\displaystyle \begin{align}

(a+b)^2+(a-b)^2 &= (a^2+2ab+b^2)+(a^2-2ab+b^2)\\ &= a^2+2ab+b^2+a^2-2ab+b^2 \\ &= a^2+a^2+2ab-2ab+b^2+b^2\\ &= 2a^2 +2b^2\,\textrm{.} \end{align}

Retrieved from "http://wiki.sommarmatte.se/wikis/2008/bridgecourse1-ImperialCollege/index.php/Solution_2.1:2e"