Solution 4.4:2c
From Förberedande kurs i matematik 1
There are two angles in the unit circle, \displaystyle x=0 and \displaystyle x=\pi, whose sine has a value of zero.
We get the full solution when we add multiples of \displaystyle 2\pi,
\displaystyle x = 0+2n\pi\qquad\text{and}\qquad x = \pi + 2n\pi\,, |
where n is an arbitrary integer.
Note: Because the difference between \displaystyle 0 and \displaystyle \pi is a half turn, the solutions are repeated every half turn and they can be summarized in one expression,
\displaystyle x=0+n\pi\,, |
where n is an arbitrary integer.