Solution 2.1:2b
From Förberedande kurs i matematik 1
We expand the first product of bracketed terms by multiplying each term inside the first bracket by each term from the second bracket
| \displaystyle \begin{align}
(1-5x)(1+15x) &= 1\cdot 1+1\cdot 15x-5x\cdot 1-5x \cdot 15x\\ &=1+15x-5x-75x^2\\ &=1+10x-75x^2\,\textrm{.} \end{align} |
As for the second expression, we can use the conjugate rule \displaystyle (a-b)(a+b)=a^2-b^2, where \displaystyle a=2 and \displaystyle b=5x,
| \displaystyle \begin{align}
3(2-5x)(2+5x) &= 3\big( 2^2-(5x)^2\big)\\ &=3(4-25x^2)\\ &=12-75x^2\,\textrm{.} \end{align} |
All together, we obtain
| \displaystyle \begin{align}
(1-5x)(1+15x)-3(2-5x)(2+5x) &= (1+10x-75x^2)-(12-75x^2)\\ &= 1+10x-75x^2-12+75x^2\\ &= 1-12+10x-75x^2+75x^2\\ &=-11+10x\,\textrm{.} \end{align} |
