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Answer 4.3:4
From Förberedande kurs i matematik 1
| a)
| \displaystyle 1-b^2
| b)
| \displaystyle \sqrt{1-b^2}
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| c)
| \displaystyle 2b\sqrt{1-b^2}
| d)
| \displaystyle 2b^2-1
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| e)
| \displaystyle \sqrt{1-b^2}\cdot\displaystyle \frac{1}{\sqrt{2}} + b\cdot \displaystyle \frac{1}{\sqrt{2}}
| f)
| \displaystyle b\cdot\displaystyle \frac{1}{2}+\sqrt{1-b^2}\cdot\displaystyle \frac{\sqrt{3}}{2}
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