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Svar 2.1:7

Version från den 31 mars 2008 kl. 12.07; Lina (Diskussion | bidrag)

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\displaystyle \displaystyle \frac{4}{(x+3)(x+5)}

\displaystyle \displaystyle \frac{x^4-x^3+x^2+x-1}{x^2(x-1)}

\displaystyle \displaystyle \frac{ax(a+1-x)}{(a+1)^2}